7. There are _____ square feet in a surface acre.
A. 5,280
B. 547,390
C. 65,200
D. 43,560
8. An acre foot of water equals:
A. 3,258 gallons
B. 32,585 gallons
C. 325,850 gallons
D. 3,258,500 gallons
Question 11 and 12 relates to the following situation:
A pond is circular, measuring 662 feet around the edge and 105 feet across. The average depth is 9 feet. Acreage is determined by multiplying the distance around the pond by itself and dividing by 547,390.
9. How many surface acres is this pond?
A. .2 B. .8 C. 1
D. 1.610. How many acre-feet of volume is this pond?
A. 1.8
B. 7.2
C. 9
D. 14.4
11. The average depth of a pond should be determined by averaging at least _____ individual soundings, uniformly spread over the entire pond surface.
A. 1
B. 5
C. 15
D. 40
12. A pond owner desires to treat a 60 feet by 120 feet area for leeches, using a rate of 13.5 pounds of copper sulfate per acre foot. Average depth of the swimming area is 3 feet. How many pounds of copper sulfate will be required to treat this swimming area?
A. .5
B. 5.0
C. 6.7
D. 67.0
13. How many acres are in a rectangular lake, 350 feet by 187 feet?
A. .5
B. 1.5
C. 5
D. 15
14. What is the average depth of a pond measuring 3, 1, 8, 7, 10, 4, 5, 2, 11, 12, 3, 5, 6, 2, and 3 feet deep?
A. 5.5
B. 6.5
C. 8.1
D. 11.7
7. Correct Answer: D
8. Correct Answer: C
9. Correct Answer: B
Surface Acres = (Total Feet of Circular Shoreline)2/547,390 = (662)2/547,390 = .8 acres
10. Correct Answer: B, OPM
Surface area in acres X average depth in feet = volume in acrefeet .8 X 9 = 7.2 acre-feet
11. Correct Answer: C, OPM
12. Correct Answer: C, A2
Explanation: Surface Area = 60 X 120/43560 = .16529 acres
Acres x 3 feet average depth = .4959 acre-feet
Acre-feet x 13.5 pounds = 6.7 pounds of copper sulfate in swimming area
13. Correct Answer: B
Surface Acres = Length X Width/43,560 = 350 X 187/ 43,560 = 1.5 acres
14. Correct Answer: A, A2
Total the Readings/Number of Readings = 82/15 = 5.5 feet average depth